y^2-12y+50=0

Solution for y^2-12y+50=0 equation:

Simplifying
y2 + -12y + 50 = 0

Reorder the terms:
50 + -12y + y2 = 0

Solving
50 + -12y + y2 = 0

Solving for variable 'y'.

Begin completing the square.

Move the constant term to the right:

Add '-50' to each side of the equation.
50 + -12y + -50 + y2 = 0 + -50

Reorder the terms:
50 + -50 + -12y + y2 = 0 + -50

Combine like terms: 50 + -50 = 0
0 + -12y + y2 = 0 + -50
-12y + y2 = 0 + -50

Combine like terms: 0 + -50 = -50
-12y + y2 = -50

The y term is -12y.  Take half its coefficient (-6).
Square it (36) and add it to both sides.

Add '36' to each side of the equation.
-12y + 36 + y2 = -50 + 36

Reorder the terms:
36 + -12y + y2 = -50 + 36

Combine like terms: -50 + 36 = -14
36 + -12y + y2 = -14

Factor a perfect square on the left side:
(y + -6)(y + -6) = -14

Can't calculate square root of the right side.

The solution to this equation could not be determined.